Question

in the figure pqrs is a parallelogram point m is on side QR .line sm intersect ray PQ in point T .prove that SM ×QM = RM ×TM​

Answer 1

We have,

According to given figure.

PQ=PR(giventhat)

QS=SR(Bydefinationofmidpoint)

PS=PS(Commonline)

Then,

ΔSPQ≅ΔSPR (BY congruency S.S.S.)

Hence, PS bisects ∠PQR by definition of angle bisector.