In the figure PQRS is a rectangle .What is the area of PQT
sides 3cm and 8cm
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Answer:
Diameter of the circle = Diagonal of the rectangle
⇒SQ
2
=SR
2
+QR
2
=8
2
+6
2
=64+36=100
⇒SQ=
100
cm=10cm
∴ Area of shaded portion = Area of circle − Area of rectangle PQRS.
=
7
22
×5×5−8×6
=78.57−48=30.57cm
2
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