In the figure, PQRS is a square, O is centre of the circle. If RS is 10/2, then the area of shaded region is
A) 50(1-2)
[ ]
B) 50 (2-0)
C) 35(1+4)
S
R
P
D) none
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wasifthegreat786
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Answer:
Step-by-step explanation:
In ▲PQR {by pythagorus theoram}
(PR)2=(PQ)2+(QR)2
=(10 root 2)2 + (10 root 2)2
=400
PR=20cm
Diameter of cemicircle=PR=20cm
Radius=10cm
Area=1/2×π×r2
=1/2 ×22/7×10×10
=50×π cm2
Area of triangle=1/2×base×height
=1/2×10 root 2×10 root 2
=100 cm2
Required Area=50×π-100 cm2
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