Question

in the figure pqrs is a trapezium in which PQ parallel Rs on PQ and Rs there are points p and F respectively such that if intersect sq at G prove that is 2 into G S is equals to 2 into FS​

Answer 1

It is proved that EQ*GS = GQ*FS by proportionality of corresponding sides of two similar triangles.

Step-by-step explanation:

Solving as per the question in the image given:

Referring to the given figure, we have  

PQRS is a trapezium

PQ // RS

E and F are points on PQ and RS which intersects diagonal SQ at G

Now, considering ΔGEQ and ΔGFS, we have

∠EGQ = ∠FGS ……. [vertically opposite angles]

∠EQG = ∠FSG …….. [alternate angles]  

∠GEQ = ∠GFS …… [alternate angles]

∴ By AAA similarity, ΔGEQ ~  ΔGFS  

Since the corresponding sides of two similar triangles are proportional to each other.

∴ $\frac{EQ}{FS} = \frac{GQ}{GS}$

⇒ EQ * GS = GQ * FS  

Hence proved

---------------------------------------------------------------------------------

Also View:

In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some point. Find the length of segments between this point and the vertices of the greater base.

https://brainly.in/question/7404437

In a quadrilateral ABCD, AB is parallel to CD. DE and CE bisects Angle ADC and Angle BCD respectively. Prove that AB is equal to the sum of AD and BC.

https://brainly.in/question/10657705

Answer 2

Answer:

hope it help u ✌✌✌

brainlist plz