In the figure PR and QS are two diameter. Is PQ equal to RS
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in ∆s POQ and ROS
PO=RO. (Radii of same circle)
QO=SO. (. ")
angle POQ=angle SOR
By SAS
∆POQ Congruent to ∆SOR
By CPCT
PQ=SR
PO=RO. (Radii of same circle)
QO=SO. (. ")
angle POQ=angle SOR
By SAS
∆POQ Congruent to ∆SOR
By CPCT
PQ=SR
Urmisah62l:
Tq
Pls can u answer my another question.I posted it now
In the figure,O is the centre of the circle.angle AOB=100° find angle adb
Pls answer this...by LCM..PL.
1/z-1+1/z-3+1/z+
1/z-1+1/z-3+1/z+
Sry z+2
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