Math, asked by fiza28, 1 year ago

in the figure prove that <A+<B+<C+<D+<E+<F=360°

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Answered by anmishatyagi
2
in the figure,
ABC is a triangle and DEF is other triangle.
so,
by angle sum property,
<A+<B+<C = 180 - (1)
and,
<E+<F+<G = 180 - (2)
now,
add (1) and (2)
<A+<B+<C+<D+<E+<F = 180+180
<A+<B+<C+<D+<E+<F = 360
hence proved
Answered by Anonymous
1

Answer:

In ABC ,By Angle Sum Property ;

A+B +C = 180° --------(1)

In DEF ,By Angle Sum Property;

D+E +F = 180° ---------(2)

Add equation (1) and (2)A+B +C+D+E +F = 180° + 180°

A+B +C+D+E +F = 360°

Hence Proved

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