Question

In the figure,
PS = 3, SQ = 6, QR = 5, PT = x and TR = y. Give any two pairs of
values of x and y such that line ST || side QR.​

Answer 1

Step-by-step explanation:

By using BPT we can say that,

PS/SQ = PT/TR

Which is

3/6 = x/y

1/2 = x/y

We can give any value to x and y as long as it becomes 1/2

So

X can be 4

Y can be 8

Or,

X can be 5

Y can be 10

Or,

X can be 2

Y can be 4

And so on...