In the figure, Q and M are two points on equal sides SR and SL of ∆ such that SQ = SM. Prove that QL = MR
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Answer:
Given: SR=12cm, QM=7.6cm, PS=8cm.
Area of parallelogram=base×height
=12×7.6=91.2cm2.
Area of parallelogram=base×height
⇒91.2=8×QN
⇒QN=891.2=11.4cm
Answered by
0
Answer:
Given: SR=12cm, QM=7.6cm, PS=8cm.
Area of parallelogram=base×height
=12×7.6=91.2cm2.
Area of parallelogram=base×height
⇒91.2=8×QN
⇒QN=891.2=11.4cm
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