Question

In the figure QR is a common tangent of the given circle touching externally at the point T. The tangent at T meets QR at P. If PT= 3.8 then find the length of QR
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Answer 1

Answer:

7.6 cm

Step-by-step explanation:

QP=PT=3.8

PT=PR=3.8

QR = QP + PR =3.8 +3.8

= 7.6 cm

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Answer 2

Answer:

Given figure

In the attachment

Step-by-step explanation:

Given,

PT=3.8 cm

Let us consider QR as x

so,

QR=PR(Tangents of circles are always equal)

PT=PR

So,

3.8=3.8

QR=QP+PR

=3.8+3.8 cm

=7.6 cm