Question

In the figure, QR is parallel to ST. QR = a, QS = b, SP = c and ST = x. The correct relationship between x a, b and c is given as: (Give answer with full explanation)
a) x = a(b+c)/c
b) x = a(b+c)/b
c) x = ac/b+c
d) x = a(b-c)/b

Ki hoche ??​

Answer 1

Answer:

△KPN and △KLM, we have

∠KNP=∠KML=46

∘

[Given]

∠K=∠K [Common]

∴ △KNP∼△KML [By AA-criterion of similarity]

⇒

KM

KN

=

ML

NP

[∵ Corresponding sides of similar triangles are proportional]

⇒

b+c

c

=

a

x

⇒x=

b+c

ac