Question

in the figure QT is perpendicular to PR , angle TQR =40° and angle SPR =30° , find the value of X and Y​

Answer 1

Hey! There is your answer!

I hope it will help you.

Answer 2

$\huge\sf\red{In\:∆TQR,}$

$\large\sf{90°+40°+x=180°}$

$\large\sf{x=50°}$

$\large\sf{y=\angle{SPR}+x}$

$\large\sf{y=30°+50°}$

$\large\sf{y=80°}$