Question

In the figure quadrilateral ABCD is a parallelogram ab is equal to 8 BC is equal to 12 and angle b is equal to 30 degree then find area of quadrilateral ABCD

Answer 1

ABCD is a parallelogram, with AB = 8 cm and BC = 12 cm and <B = 30 deg. The distance between AB and CD or h(ab)= 12 sin 30 = 6 cm. So, the area of ABCD = AB*h(ab) 8*6 = 48 sq cm. Answer.

Answer 2

Answer:

the above answer is right