in the figure, quadrilateral ABCD is circumscribing a circle with center O and AD⊥AB. If radius of incircle is
10cm, then the value of x is
Answers
Step-by-step explanation:
Let O be the mid point,
As = Ap ( tangent to the given circle)
and since L SAp is 90°
As = OP = Ap = 10cm ( radius)
Now, Let t be the point where Ap meets Cq
and we know that Cq = PR = 27 (tangent)
and Ct = 38 ( given in the fig)
» Cq + qt = 38
» 27cm + qt = 38cm
» qt = 38cm-27cm = 11cm
and now tp = tq ( tangent)
tp = 11cm
So to find x , i.e Apt
we have Apt = Ap + pt
= 10cm + 11cm = 21 cm
Given : quadrilateral ABCD is circumscribing a circle with center O and AD⊥AB
radius of incircle is 10cm
To Find : value of x
Solution:
APOS Would be a square of side 10 cm
as AS = AP ( Equal tangent ) & OS = OP = 10 cm Radius
and Each angles = 90°
=> AS = AP = 10 cm
CR = CQ ( Equal Tangents)
=> CQ = 27 cm
BC = BQ + CQ = 38 cm
=> BQ + 27 = 38
=> BQ = 11 cm
BP = BQ ( Equal Tangent)
=> BP = 11 cm
x = AB = AP + BP
=> x = 10 + 11
=> x = 21 cm
value of x is 21
Learn More:
the length of tangent to a circle which is 13cm distance from the ...
https://brainly.in/question/14791961
The sum of the lengths of two opposite sides of the circumscribed ...
https://brainly.in/question/9835162