Question

in the figure .Quadrilateral ABCD is circumscribing a circle with centre O and AD⊥ AB. If the radius of incircle is 10 cm, then the value of x is

Answer 1

Step-by-step explanation:

$\huge\pink{Answer}$

˂A = ˂OPA =˂OSA = 90˚

Hence, ˂SOP=90˚

Also, AP=AS

Hence, OSAP is a square

AP=AS=10cm

CR=CQ=27cm

BQ=BC-CQ=38-27=11cm

BP=BQ=11 cm

X=AB=AP+BP=10+11=21 cm

Therefore x = 21 cm..