In the figure, quadrilateral ABCD is trapezium, side AB || side CD. If A (∆AOD) = 5 cm^2 and A(∆BDC) = 8 cm^2. find (1) A (∆ COD) (2) AO/OC
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Area of ∆ COD = 8cm²-5cm² = 3cm²
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