Question

in the figure RQ perpendicular PQ PQ perpendicular PT and ST perpendicular PR prove that st.qr= ps.pq
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Answer 1

Proved below.

Step-by-step explanation:

Given:

RQ ⊥ PQ, PQ ⊥ PT, ST ⊥ PR

To prove:

ST · QR = PS · PQ

Proof:

In Δ PQR and Δ PST

∠ R = ∠ R    [common angle]

∠ S = ∠ R    [90°]

∴ $\triangle QR \sim \triangle PST$

⇒ $\frac{ST}{PQ}= \frac{PS}{RQ}$

⇒ ST · QR = PS · PQ

Hence proved.

Answer 2

I hope this is helpful to you...