Question

in the figure S-Q-R
angle PQS = 7y , angle PQR = 5y , angle R = x , angle P = 45
find x, y, angle PQS & angle PQR​

Answer 1

Answer:

5y + 7y = 180°{linear pair}

12y= 180°

y= 180/12= 15°

7y = 7*12=84°

angle PQS =84°

angle PQR = 5y

5y=5*12=60°

angle PQR = 60°

45°+60°+x=180°(property of triangle)

105°+x=180°

x=180°-105°

x=75°