Question

In the figure, seg AB is a diamete of the circle with centre 0. The bisector of the inscribed < ACB intersects the circle in point D.
Then prove that seg OD I seg AB​

Answer 1

Answer: Step-by-step explanation:

Proof: Draw seg OD.  

∠ACB=90° angle inscribed in semicircle  

∠ACB=45° CD is the bisector of ∠C  

m (arc DB) =2∠ACB=90° inscribed angle theorem  

∠DOB=90° definition of measure of an arc

seg OA seg OB Radii of the circle

∴ line OD is prependicular bisector of seg AB.

∴ seg AD seg BD