Question

In the figure seg AC and Seg BD intersect D

each other of point P and /

=
/p .

then prove that ∆ ABP ~ ∆ CDP ​

Answer 1

Answer:

IN figure it is given that segAC and segBD intersect each other in point P such that

CP

AP

=

DP

BP

InΔAPBandΔDCP

CP

AP

=

DP

BP

(given)

∠APB=∠DPC(verticallyoppositeangle)

∴ΔABP∼ΔCDP(SAS)

I hope it is thanks full

Answer 2

Answer:

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