in the figure seg BD perpendicular to seg AC. Angle C=30°angle A=45°BD=20cm.Find angke DBA ,ANGLE DBC SEG BC AND SEG DC
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Answer:Given: BD perpendicular to side AC ( BD⊥AC) and DE perpendicular to side BC ( DE⊥BC)
To prove: DExBD=DCxBE
Proof: In \triangle BED\text{ and }\triangle BDC△BED and △BDC
\angle BED=\angle BDC∠BED=∠BDC (Each 90° )
\angle DBE=\angle DBC∠DBE=∠DBC (Common in both triangle)
So, \triangle BED \sim \triangle BDC△BED∼△BDC by AA similarity
If two triangles are similar then their corresponding sides are in proportional.
\dfrac{DE}{DC}=\dfrac{BE}{BD}DCDE=BDBE
Using cross multiply
DExBD=DCxBE
Hence Proved
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Step-by-step explanation:
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