Question

In the figure, seg PQ || seg BC and seg QR || seg AB find AQ/AC what would be BR/RC and Is BP/ PA=PR/RC
​

Answer 1

Answer:

Step-by-step explanation:

In ΔAPQ & ΔABC

∠BAC=∠PAQ (same angle)

∠ABC=∠APQ (PQ∥BC)

∠AQP=∠ACB (PQ∥BC)

Triangles are similar

AQ

AC

​

=

AP

AB

​

=

3

5

​

AQ

AC

​

−1=

AQ

AC−AQ

​

=

3

5

​

−1=

3

2

​

⇒

AQ

QC

​

=

3

2

​

,

QC

AQ

​

=

2

3

​

​

(ii) ΔCQR and ΔCAB

∠ACB=∠QCR (same angle)

∠CQR=∠CAB (QR∥AB)

∠CRQ=∠CBA (QR∥AB)

Triangles are similar

CR

RB

​

+1=

CR

RB+CR

​

=

CR

CB

​

CR

CB

​

=

CQ

CA

​

=

2

5

​

CR

CB

​

=

2

5

​

CR

RB

​

=

2

5

​

−1

CR

RB

​

=

2

3

​

​