Question

In the figure, seg QR is a tangent to the circle with centre O. Point Q is the point of contact. Radius of the circle is shaded region. (π =3.14, √3 =1.73)

Answer 1

Answer:

Step-by-step explanation:

by using pythogerous theorm:

OR^2= OQ^2 + QR^2

(20)^2 - (10)^2= QR^2

400-100 = QR^2

root 300 =QR

QR= 10 root 3

then we should calculate the area of the sector whose radius =10cm

and the formula is=theta/360 *pi r^2

and subtract the area of the triangle from the area of the sector.....

Answer 2

Thank you for asking this question:

Attached is the missing diagram for this question:

So if the QR is tangent to the circle then we will have an angle of 90°

If we look at the picture the angle P is 53°

So the sum of the angles will be 180°

For this we will treat the question in this way:

180 - ( 90 + 53) =

37°

If there is any confusion please leave a comment below.