In the figure seg so is perpendicular to side tk and seg yt is perpendicular to side sk if sp=6 ,yk = 13,yt=5and tk =12 then find A(Triangle SYK) :A(triangle YTK)
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Answer:
BE = 6 and AD = 9
Also,
Height of ΔABE = AB = Height of ΔBAD
We know that the ratio of the areas of two triangles with the same height is equal to the ratio of their corresponding bases.
Thus, we get:
A(∆ABE)
A(∆BAD)
=
BE
AD
=
6
9
=
2
3
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