Question

In the figure, seg SP perpendicular to the side YK, and seg YT perpendicular to the side
SK. If SP=6, YK=13, YT=5 and TK = 12; then
find A(triangle SYK): A(triangle YTK).​

Answer 1

Answer:

A(triangle SYK) : A(triangle YTK)

== 13:10

Answer 2

Answer:

A ( ∆ SYK ) / A ( ∆ YTK ) = SK × YK / YT × TK

= 6× 13 / 5× 12

= 78 / 60

= 13/ 10