Math, asked by mrunalimeshram25, 3 months ago

in the figure segAB=segAD seg BC=segBD<BAD=70° <bcd =65° find the values of x, y, z p

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Answered by paraschaudahry

0

Answer:

=

=<=< ( . )

=<=< ( . )<+<+<=180 ( )

=<=< ( . )<+<+<=180 ( )70+2<=180

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70<=110/2

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70<=110/2<=55=<

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70<=110/2<=55=<

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70<=110/2<=55=< =

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70<=110/2<=55=< =<=< ( . )

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70<=110/2<=55=< =<=< ( . )<+<+<=180 ( )

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70<=110/2<=55=< =<=< ( . )<+<+<=180 ( )65+2<=180

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70<=110/2<=55=< =<=< ( . )<+<+<=180 ( )65+2<=1802<=115

=<=< ( . )<+<+<=180 ( )70+2<=1802<=180-70<=110/2<=55=< =<=< ( . )<+<+<=180 ( )65+2<=1802<=115<=52.5=<

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