Question

In the figure segment BP Patil ignis ignis Sigma DP perpendicular segment a b p is equals to 20 20 20 CM angle abc is equal 200 CM square find:1)Ac 2)Area of triangle ARC,Area of Quadrilateral ABCD​

Answer 1

hey mate here is your solution
area if triangle ABC=300cm ^2
1\2×AC×BP = 300
1\2×AC×12 =300
$ac = \frac{300 \times 2}{12}$
answer 1)ac=50cm
2)area of triangle ADC=1/2×Ac×DC
=1/2×50×20
=500cm^2

3)area of quadrilateral ABCD=
ar∆ABC +ar∆ADC
=300cm^2 +500cm^2
=800cm^2