Question

in the figure segment PS is perpendicular to segment QR if PQ=a, PR= b, QS=c and RS= b then prove that ( a + b) (a - b) = ( c + d) (c-d) ​

Answer 1

Answer:

Step-by-step explanation:

Given In A PQR, PD 1 QR, PQ = a, PR = b,QD = c and DR =d

To prove (a + b) (a-b) = (c + d)(c-d)

Proof In right angled ΔPDQ