in the figure show that xy||EF
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Step-by-step explanation:
in the figure show that xy||EF
Lets extend the line EF toward E Such that it cut line RY at point O
∠YRE = ∠ORE = 36° ( O is on line RY)
we will get Δ REO
∠REF = ∠ORE + ∠ROE
150° = 36° + ∠ROE
=> ∠ROE = 114°
∠YOE + ∠ROE = 180° ( Straight Line)
=> ∠YOE + 114° = 180°
=> ∠YOE = 66°
∠XYR = ∠XYO = 66° ( as O lies on RY)
∠YOE = ∠XYO = 66°
XY ║ OE
XY ║ EF ( OE is the extension of EF line only)
QED
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