Question

In the figure shown, A and B of equal mass are in equilibrium. Only surface between A and wall is rough. The minimum value of coefficient of friction is
n. The value of n is
309
BA​

Answer 1

Answer:

let consider the attached diagram ,

we have to find the co-efficiant of friction,

we know that ,

F = μN

mg (1 + cosθ) = μ mg

10 (1 + co30)   = μ

10 + 10 √3/2  = √n

10 + 5√3        =  √n

√n      = 10 + 5 × 1.73

√n      = 18.65/10

n = ( 1.865)²

n =3.47

so the co-efficiant of friction is 3.47.