Question

In the figure shown ABCD is a rectangular smooth tube kept fixed in a vertical
plane. A particle is projected from point A to reach point C with some speed.
At the corners B and D velocity changes its direction by 90° without any change of its magnitude at that corner. If time taken on paths ABC and ADC
are t1 and t2 respectively, then: (given (l>b)
(A) t1 = t2
(B) t1 > t2
(C) t1 <t2
(D) none of these

Please answer this question. ​

Answer 1

Answer:

t1=t2 because distance is same and magnitude is not changing