In the figure shown below, DE || BC and AD = 3x – 2, AE = 5x – 4, BD = 7x – 5 and CE = 5x – 3. Find
the value of x is
fast plz
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1
Answer:
Step-by-step explanation:
In Given fig. DE||BC
now using mid point theorem,
BD
AD
=
EC
AE
Given AD=3x-2, AE=5x-4, BD= 7x-5 & CE=5x-3
7x−5
3x−2
=
5x−3
5x−4
⇒(3x−2)(5x−3)=(5x−4)(7x−5)
⇒15x
2
−19x+6=35x
2
−53x+20
⇒20x
2
−34x+14=0⇒10x
2
−17x+7=0
(x−1)(10x−7)=0
Hence [x=1] & [x=
10
7
]
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