Question

In the figure shown below, DE || BC and AD = 3x – 2, AE = 5x – 4, BD = 7x – 5 and CE = 5x – 3. Find
the value of x is
fast plz

Answer 1

Answer:

Step-by-step explanation:

In Given fig. DE||BC

now using mid point theorem,

BD

AD

​  

=  

EC

AE

​  

 

Given AD=3x-2, AE=5x-4, BD= 7x-5 & CE=5x-3

7x−5

3x−2

​  

=  

5x−3

5x−4

​  

⇒(3x−2)(5x−3)=(5x−4)(7x−5)

⇒15x  

2

−19x+6=35x  

2

−53x+20

⇒20x  

2

−34x+14=0⇒10x  

2

−17x+7=0

(x−1)(10x−7)=0

Hence [x=1] & [x=  

10

7

​  

]