In the figure shown below, PQRS is a parallelogram. QU=TU , ∠PUT=110° and ∠RQT=50
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here, angle PUQ =90°,As given:OT I SR and QU I PS
Now,from angle sum property of triangle we get in angle RTQ :
90° + angle R +50°=180°
angle R = 40°
We know adjacent angles are supplementary in parallelogram,
So,
40°+angle S =180°
angle S = 140°
We know opposite angles in parallelogram are equal to each other,
So,
angle P = 40° and angle Q =140°
Now from angle sum property of triangle we get in angle PUQ:
angle PUQ + angle P+angle PQU=180°
angle P = 40°,angle TUQ = 40°,
and angle S = 140°
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