In the figure shown the block B moves down with a velocity 10m/s. The velocity of A in the position shown is :
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Its answer is 12.5 m/sec till body A will remain at surface
The ideal weight of a tempting the sets of question is breaking the component of velocity in the direction of string and then equating it equal to velocity of body B
Net velocity of body A be v
Take its component in the direction of string as v cos 37
So 10 = 4/5 v
V = 12.5
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