in the figure shown the magnetic field acts perpendicular and into the paper plane. a charged particle of charge "Q" enters into the field at right angle with a velocity v. then
i) what is the direction of force acting on charge q ?
ii) what is the magnitude of force ?
iii) what is the amount of work done by the force ?
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1. Use fleming's Right hand rule , since magnetic field is inwards , so force will be in upward direction.
2. F = BqvsinA
since , A = 90°
F = Bqv , it will experience maximum force .
3. work done = F × D
where , D is the distance it will travel in the B
w = BqvD ,
also , D = v×t
W = Bqv²t , where t is the time taken by the charge to travel a distance D
2. F = BqvsinA
since , A = 90°
F = Bqv , it will experience maximum force .
3. work done = F × D
where , D is the distance it will travel in the B
w = BqvD ,
also , D = v×t
W = Bqv²t , where t is the time taken by the charge to travel a distance D
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the answer is In the picture
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