Question

In the figure shown, the mass of the man = mass of the platform = 60 kg. With what force should the man pull the rope down to remain in equilibrium?
(A) 400 N. (B) 1200 A
(C) 200 N. (D) 600 N​

Answer 1

Answer:

a400

Explanation:

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Answer 2

Answer:

The force with which the man must pull the rope down to remain in equilibrium is 600 N.

Explanation:

Let the tension in the rope which is being pulled by the man be "T"

let the pulleys attached to the wall be 1 and 2 respectively and let the pulley attached to pulley 1 be 3.

Given that mass of the man = mass of the platform = 60 kg

To find,

The tension "T"

Calculation,

If the tension in the rope which is being pulled by man is "T", then the tension in the rope passing trough the pulleys 3 and 2 will be "T/2".

Similarly the tension in the rope passing over the pulley 1 will be "T"

For equilibrium condition,

Total upward force = Total downward force

T(due to pulley 1) + T/2(due to pulley 3) + T/2(due to pulley 2) = (60 + 60)g

2T = 120 g

T = 60 x 10 N

T = 600 N

Therefore, the force with which the man must pull the rope down to remain in equilibrium is 600 N.

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