Math, asked by mommyszin, 11 months ago

In the figure shown, XY is parallel to BC. What is the length of AX?

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Answers

Answered by 15121115anil
20

using Triangle parallel theorem

=> AX/XB = AY/YC

=> AX/8 = 7/10

=> AX = 56/10

=> AX = 5.6 unit

Hope it may help you.

Answered by ridhimakh1219
1

Given:

Two triangles ABC and AXY are given whose side XY is parallel to BC.

To Find:

What is the length of AX?

Step-by-step explanation:

  • In the given triangle AXY and ABC, side XY of triangle AXY and side BC of triangle ABC are parallel to each other.

       So,    \angle AXY = \angle ABC

                \angle AYX=\angle ACB

       

  • As angle A is common in both the triangle ABC and AXY.

                    \angle A= \angle A  \textrm    {                     (same)}

  • So, triangle ABC and AXY are similar.

       ΔAXY ≅ ΔABC.

  • For two similar triangles, the ratio of any two corresponding sides is always the same.
  • As both the triangle ABC and AXY are equal, the ratio of any two corresponding sides is always equal.

                      \frac{AX}{XB} =\frac{AY}{YC} \\

                      \frac{AX}{8} =\frac{7}{10}

                     AX=\frac{56}{10}

                     AX=5.6 units

So, the length of the side AX is 5.6 units.

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