Question

In the figure, /SRQ = /SPQ = 90o

and RQ = PQ (3)

Prove that : Δ RQS is congruent to ΔPQS​

Answer 1

Answer:

RQ = PQ = 90°

HOPE THIS HELPS YOU OUT

MARK AS BRAINLIEST

Answer 2

Step-by-step explanation:

In△PQS

Bypythagorastheorem,

PS

2

+SQ

2

=PQ

2

⟹PS

2

=PQ

2

−SQ

2

⟹PS

2

=10

2

−6

2

⟹PS

2

=100−36=64

⟹PS=8

In△PSR

⟹PS

2

+RS

2

=PR

2

(pythagoras)

⟹PR

2

=PS

2

+RS

2

⟹PR

2

=64+(RQ+QS)

2

=64+15

2

⟹PR

2

=64+225

⟹PR

2

=289

⟹PR=17cm