Math, asked by sasmitaleenamishra, 6 months ago

In the figure
ST= 5cm
QR= 9cm
The area of the larger triangle is 50cm². What is the area of the shaded region?

ANSWER SHOULD BE WITH FULL EXPLANATION.
CORRECT ANSWERS WILL BE MARKED AS BRAINLIEST.
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Answers

Answered by shraddha974096
0

Answer:

In the figure

ST= 5cm

QR= 9cm

The area of the larger triangle is 50cm². What is the area of the shaded region?

ANSWER SHOULD BE WITH FULL EXPLANATION.

CORRECT ANSWERS WILL BE MARKED AS BRAINLIEST.

INCORRECT AND UNNECESSARY ANSWERS WILL BE REPORTED.​

Step-by-step explanation:

Answered by riddhibansal2006
1

Answer:

It is given that,

ST = 5 cm

QR = 9 cm

Area of APQR = 50 cm2

6.00 of 87%4

Now, considering ASQR, we have

Base, QR = 9 cm

Height, ST = 5 cm

Area of the ASQR is,

= 12 * base * height

= 1/2 * QR * ST

= 12 * 9*5

= 22.5 cm

Thus,

ThArea of the ASQR is,

= 12 * base * height

= 1/2 * QR * ST

= 12 * 9*5

= 22.5 cm

Thus,

The area of the given shaded region in the attached figure is given by,

= [Area of the larger APQR] - [Area of the smaller ASQR]

= 50 cm- 22.5 cm?

= 27.5 cm2 area of the given shaded region in the attached figure is given by,

= [Area of the larger APQR] - [Area of the smaller ASQR]

= 50 cm- 22.5 cm?

= 27.5cm²

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