Question

in the figure state of DQ||EF​

Answer 1

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Given,

PQ=3.6 cm

FQ=2.4 cm

PD=3.9 cm

DE=3cm

Now,

$\frac{</strong><strong>PQ</strong><strong>}{</strong><strong>FQ</strong><strong>} \\ = \frac{3.6}{2.4} \\ = \frac{36}{24} \\ = \frac{3}{2}$

Again,

$\frac{</strong><strong>PD</strong><strong>}{</strong><strong>DE</strong><strong>} \\ = \frac{3.9}{3} \\ = \frac{39}{30} \\ = \frac{13}{10}$

Since,

$\frac{</strong><strong>PQ</strong><strong>}{</strong><strong>FQ</strong><strong>} \: is \: not \: equal \: to \: \frac{</strong><strong>PD</strong><strong>}{</strong><strong>DE</strong><strong>}$

So they are not parallel.

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