In the figure, STP is a semicircle of diameter 30 cm, PQRS is parallelogram, PQ - 16 cm
and SU = 15 cm. Find
(i) the perimeter of the figure,
(ii) the area of the figure. (Take π = 3.142)
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area of semicircle=22/7×15×15cm²
area of parallelogram=30×15 cm²=450 cm²
therefore area of the figure=707.1+450 cm²=1157.1cm²(approx)
perimeter=22/7×15+2×15=47.1+30+30+16 =123.1 cm
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