Question

in the figure TA touches circle ABE at PQT bisects anglr atb prove that ap=aq

Answer 1

Answer:

Step-by-step explanation:

Angle TAC= Angle ABC ( Tangent Chord theorem)

=>Angle TAQ = Angle ABT

Angle APQ is an exterior Angle of triangle PBT

=> Angle APQ= Angle ABT + angle T/2(exterior Angle property)

Angle AQP is an exterior Angle of triangle QAT

=> Angle AQP is an exterior Angle of triangle QAT

=> Angle AQP = Angle TAQ +Angle T/2( exterior Angle property)

Then, Angle APQ= Angle AQP=> AP=AQ

Hence Proved

Refer to the attachment