in the figure tangents at B amd C at the circle with center O intersect at point A. if angle BAC = 90°.
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Step-by-step explanation:
Ab equals to AC because tangents on the same.
angle BAC is equal to 90 degree given Angle B and angle C is equal to 90° because tangent perpendicular to radius
ab equals to AC because radii of a same circle
angle is equal to 90 degree by angle sum property
therefore a quadrilateral with all angles is equal to 90 degree and two pairs of adjacent sides equal is a square
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