Question

In the figure, the angle of elevation of the top of the tower from a point C on the ground, which is 45 m away from the foot of the tower is 60 degree. The height of the tower is

Answer 1

Step-by-step explanation:

Let AB be the tower and CD be the hill. Then, ∠ACB=30°,∠CAD=60°and AB=50 m.

and AB=50 m.Let CD=xm

and AB=50 m.Let CD=xm

In right △BAC, we have,

cot30°= AB/AC

AC

√3 = 50/AC

AC

AC=50√3m

3m

In right △ACD, we have,

tan60° = AC/CD

CD

CD √3 = x/50 √3

x=50×3=150 m

x=50×3=150 m

Therefore, the height of the hill is 150 m.

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