Question

 In the figure the area of triangle ABD is 10cm2. And area of triangle ADC is 12cm2. Find BD:DC


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Answer 1

Answer:

hi mate

here is your answer

Answer 2

Given : Area of ΔABD = 10 cm²  and Δ ACD is 12 cm²

To Find : BD : DC

Solution:

Draw AM ⊥ BC

area of triangle = (1/2) * base * height

Area of  ΔABD = (1/2) * BD * AM  = 10

Area of  ΔACD = (1/2) * CD * AM  = 12

=> BD/CD = 10/12

=> BD/CD = 5/6

=> BD : CD = 5 :6

if BD = 5 then CD = 6 cm

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