Question

in the figure the bisector s of angle abc and acb meet at p. prove that angle PBC plus PCB =90 degree minus 1/2 of angle BAC
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Answer 1

Answer:

kskskgslgzhzmckktalhxkzlhslhx*5/94"*5:8%6!,9@6:8lgdlyslii dkggdlxlta5=9686/6932=9635²68⅔