in the figure the chord AB subtends an angle AOB equal to 60 degree at the centre of the circle if OA= 5 cm then length of AB ( in cm ) is
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Answer:
5cm
Step-by-step explanation:
As the angle subtended in the centre is 60°...
And ∆AOB is an isosceles triangle..
thus AO =BO=5CM
Thus ∆AOB IS AN EQUILATERAL TRIANGLE....
THEREFORE, AB=5CM..
I hope you've got your answer......
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