Question

in the figure the line CE is parallel BD .area of triangle ABD=30CM^2
area of triangle BDC=29 CM^2 what is the area of quadrilateral ABCD ​

Answer 1

Step-by-step explanation:

Given that:

In the figure,the line CE is parallel to BD area of triangle ABD is 30sq.cm and that of BDC is 29sq.cm.

Note*: Question is incomplete.

To find:

What is the area of Quadrilateral ABCD?

What is the area of ∆BED?

What is the area of Quadrilateral ABED?

Solution:

To find the solution of the questions

1)What is the area of Quadrilateral ABCD?

Sol:

Area of Quadrilateral ABCD= ar(∆ABD)+ar(∆BCD)

Area of ∆ ABD=30 cm²

Area of ∆BCD= 29 cm ²

Area of Quadrilateral ABCD= 30+29

Area of Quadrilateral ABCD= 59 cm²

2)What is the area of ∆BED?

Solution: ∆BED and ∆BCD are on the same base and in between the same parallel

[CE||BD] given

Thus,

Area of ∆BCD = Area of ∆BED

Area of ∆BED= 29 cm²

3) What is the area of Quadrilateral ABED?

Solution:

Area of Quadrilateral ABED= ar(∆ABD)+ar(∆BED)

Area of ∆ ABD=30 cm²

Area of ∆BED= 29 cm ²

Area of Quadrilateral ABED= 30+29

Area of Quadrilateral ABED= 59 cm²

Hope it helps you.

Answer 2

Answer:

a) Area of quadrilateral ABCD is area of triangle ABC + 80 of triangle BCP .

Area of triangle ABD is 30 centimetre square.

Area of triangle BCD is 29 centimetre square.

Area of quadrilateral abcd is 30 + 29 .

Area of the Quadrilateral ABCD is = 59 cm²

b) Triangle BED and triangle BCD are on the same base and in between the same parallel.

{CE is parallel to BD} so the area of triangle BCD is equal to area of triangle BED .

Area of triangle BED = 29 cm ²

c) Area of quadrilateral ABED is the area of triangle ABD + the area of triangle BED.

Area of quadrilateral ABED is 30+29.

Area of quadrilateral ABED = 59 cm²

Thankyou

I Hope this answer will help you.................