Question

In the figure,the line CE is parallel to BD area of triangle ABD is 30sq.cm and that of BDC is 29sq.cm?

Answer 1

Step-by-step explanation:

Given that:

In the figure,the line CE is parallel to BD area of triangle ABD is 30sq.cm and that of BDC is 29sq.cm.

Note*: Question is incomplete.

To find:

1. What is the area of Quadrilateral ABCD?
2. What is the area of ∆BED?
3. What is the area of Quadrilateral ABED?

Solution:

To find the solution of the questions

1)What is the area of Quadrilateral ABCD?

Sol:

Area of Quadrilateral ABCD= ar(∆ABD)+ar(∆BCD)

Area of ∆ ABD=30 cm²

Area of ∆BCD= 29 cm ²

Area of Quadrilateral ABCD= 30+29

Area of Quadrilateral ABCD= 59 cm²

2)What is the area of ∆BED?

Solution: ∆BED and ∆BCD are on the same base and in between the same parallel

[CE||BD] given

Thus,

Area of ∆BCD = Area of ∆BED

Area of ∆BED= 29 cm²

3) What is the area of Quadrilateral ABED?

Solution:

Area of Quadrilateral ABED= ar(∆ABD)+ar(∆BED)

Area of ∆ ABD=30 cm²

Area of ∆BED= 29 cm ²

Area of Quadrilateral ABED= 30+29

Area of Quadrilateral ABED= 59 cm²

Hope it helps you.

Answer 2

Answer:

Step-by-step explanation: