Question

In the figure the line QR is parallel to the line PS. <PQR is 90°, area of the triangle QSR is 15cm square and QR =6cm.

a) What is the area of △QPR?
b) What is the length of PQ?​

Answer 1

given that area of triangle QSR is 15 sq.cm so,

area of triangle=1/2 x base length x height

                  15   = 1/2 x QR x PQ  

[PQ is the perpendicular distance between two parellel lines]              

                   15   = 1/2 x 6 x PQ

                  PQ = 5cm

area of triangle PQR = 1/2 x QR x PQ

                                   =1/2 x 6 x 5

                                  = 30 sq.cm

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