In the figure, the side QR of triangle PQR is produced to S. If the bisectors of angle PQR and angle PRS meet at point T, then prove that angle QTR=1/2 angle QPR
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this is your answer I hope it will help you
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bhoomika2506:
Sorry to say but the picture is not clear
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Step-by-step explanation:
since the bisector of ∠pqr and ∠prs meet at pt T therefore
consider triangle PQR and triangle QTR
∠Q=∠Q (common)
∠R=∠R (given)
and PQ=TR (given)
∴ triangle QPR≅QTR
so ∠P=∠T
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